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expm1, expm1f, expm1l - exponential minus
1
#include <math.h>
double expm1(double x);
float expm1f(float x);
long double expm1l(long double x);
expm1(x) returns a value equivalent to ‘exp (x) - 1’. It is computed
in a way that is accurate even if the value of x is near zero--a case where
‘exp (x) - 1’ would be inaccurate due to subtraction of two numbers that are
nearly equal.
BSD, C99. The float and the long double variants
are C99 requirements.
exp(3)
, log(3)
, log1p(3)
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